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Proof step 19 from proof valid-global-sqn-next (previous step)

apebs[m] = mkpeb(aehdr, avhdr, buf, m1, boolvar), m < # apebs, n ≤ valid-sqns(v, m0, apebs, m).max, ∀ v, m0. valid-sqns(v, m0, apebs, m) ≠ ∅ → valid-sqns(v, m0, apebs, m).max < n, ¬ valid-peb(mkpeb(aehdr, avhdr, buf, m1, boolvar)) ∨ avhdr.sqn < n ⊦ valid-sqns(v, m0, apebs, m) = ∅, valid-peb(v, m0, mkpeb(aehdr, avhdr, buf, m1, boolvar))

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: v, m0

Additional information

Used simplifier rules: ⊦ m ≤ n → (n < m ↔ false); (s) Used terms: v, m0