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Proof step 1 from proof valid-global-sqn-not-leq (conclusion)

⊦ valid-sqns(v, m, apebs) ≠ ∅ ∧ valid-global-sqn(apebs, n) → ¬ n ≤ valid-sqns(v, m, apebs).max

System applied rule normalize

And obtained the following new goals

Proof step 2:
valid-global-sqn(apebs, n), n ≤ valid-sqns(v, m, apebs).max ⊦ valid-sqns(v, m, apebs) = ∅

Rule argument

Additional information