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Proof step 22 from proof valid-global-sqn-write-valid (previous step)

apebs[m] = mkpeb(aehdr, avhdr, buf0, m0, boolvar0), m < # apebs, valid-peb(mkpeb(aehdr, avhdr, buf0, m0, boolvar0)), valid-peb(mkpeb(aehdr, avhdr, buf1, m1, boolvar1)), valid-peb(v, m2, mkpeb(aehdr, avhdr, buf0, m0, boolvar0)), n ≤ valid-sqns(v, m2, apebs).max, ∀ v, m2. valid-sqns(v, m2, apebs) ≠ ∅ → valid-sqns(v, m2, apebs).max < n ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: v, m2

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n → (n ≤ m ↔ false); (s)%n < # apebs ⊦ apebs[n] = apeb ∧ valid-peb(v, m, apeb) → valid-sqns(v, m, apebs) ≠ ∅; (s)% ⊦ m ≤ n → (n < m ↔ false); (s) Used terms: v, m2