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Proof step 2 from proof valid-vtbl-sqns-notempty (previous step)

valid-sqns(VTBL_VOLID, VTBL_LNUM, apebs) = ∅, valid-vtbl(apebs, vols, wlar, n0), valid-wl(apebs, wlar) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
apebs[n0].vidhdr.leb = VTBL_LNUM, wlar[n0].status = used, apebs[n0].vidhdr.vol = VTBL_VOLID, valid-sqns(VTBL_VOLID, VTBL_LNUM, apebs) = ∅, n0 < # wlar, n0 < # apebs, is-encoded(to-vtbl(vols), apebs[n0].data), ∀ n. n < # wlar → (wlar[n].status = erroneous ↔ apebs[n].bad) ∧ (wlar[n].status = free → apebs[n].vidhdr = empty) ∧ (wlar[n].status ≠ erroneous ∧ wlar[n].status ≠ erasing → apebs[n].echdr = aechdr(wlar[n].ec)) ∧ (wlar[n].status = used → (∃ v, m. valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max)) ⊦

Rule argument

Additional information

Used simplifier rules: valid-wl: ⊦ valid-wl(apebs, wlar) ↔ (∀ n. n < # wlar → (wlar[n].status = erroneous ↔ apebs[n].bad) ∧ (wlar[n].status = free → apebs[n].vidhdr = empty) ∧ ( wlar[n].status ≠ erroneous ∧ wlar[n].status ≠ erasing → apebs[n].echdr = aechdr(wlar[n].ec)) ∧ ( wlar[n].status = used → (∃ v, m. valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max)));%valid-vtbl: ⊦ valid-vtbl(apebs, vols, wlar, n0) ↔ n0 < # apebs ∧ n0 < # wlar ∧ wlar[n0].status = used ∧ apebs[n0].vidhdr.vol = VTBL_VOLID ∧ apebs[n0].vidhdr.leb = VTBL_LNUM ∧ is-encoded(to-vtbl(vols), apebs[n0].data);% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic