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Proof step 6 from proof valid-vtbl-sqns-notempty (previous step)

avhdr.leb = VTBL_LNUM, avhdr.vol = VTBL_VOLID, apebs[n0] = mkpeb(aehdr, avhdr, buf, m0, boolvar), wlar[n0] = wl-entry(m1, stat), stat = used, valid-sqns(VTBL_VOLID, VTBL_LNUM, apebs) = ∅, n0 < # apebs, n0 < # wlar, is-encoded(to-vtbl(vols), buf), ∀ n. n < # wlar → (wlar[n].status = erroneous ↔ apebs[n].bad) ∧ (wlar[n].status = free → apebs[n].vidhdr = empty) ∧ (wlar[n].status ≠ erroneous ∧ wlar[n].status ≠ erasing → apebs[n].echdr = aechdr(wlar[n].ec)) ∧ (wlar[n].status = used → (∃ v, m. valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max)) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
avhdr.leb = VTBL_LNUM, avhdr.vol = VTBL_VOLID, wlar[n0] = wl-entry(m1, used), apebs[n0] = mkpeb(aehdr, avhdr, buf, m0, boolvar), valid-sqns(VTBL_VOLID, VTBL_LNUM, apebs) = ∅, n0 < # wlar, n0 < # apebs, is-encoded(to-vtbl(vols), buf), ∀ n. n < # wlar → (wlar[n].status = erroneous ↔ apebs[n].bad) ∧ (wlar[n].status = free → apebs[n].vidhdr = empty) ∧ (wlar[n].status ≠ erroneous ∧ wlar[n].status ≠ erasing → apebs[n].echdr = aechdr(wlar[n].ec)) ∧ (wlar[n].status = used → (∃ v, m. valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max)) ⊦

Proof step 6 from proof valid-vtbl-sqns-notempty (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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