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Proof step 13 from proof valid-wl-erasing-invalidate (previous step)

# apebs = # wlar, wlar[m] = wl-entry(m0, erasing), apebs[n] = mkpeb(aehdr1, avhdr1, buf1, m4, boolvar0), wlar[n] = wl-entry(m5, stat), m < # wlar, n < # wlar, ∀ n. n < # wlar → (wlar[n].status = erroneous ↔ apebs[n].bad) ∧ (wlar[n].status = free → apebs[n].vidhdr = empty) ∧ (wlar[n].status ≠ erroneous ∧ wlar[n].status ≠ erasing → apebs[n].echdr = aechdr(wlar[n].ec)) ∧ (wlar[n].status = used → (∃ v, m. valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max)) ⊦ n = m, valid-peb(mkpeb(aehdr, avhdr, buf, m2, false)), (stat = erroneous ↔ boolvar0) ∧ (stat = free → avhdr1 = empty) ∧ (stat ≠ erroneous ∧ stat ≠ erasing → aehdr1 = aechdr(m5)) ∧ ( stat = used → (∃ v, m1. valid-peb(v, m1, mkpeb(aehdr1, avhdr1, buf1, m4, false)) ∧ avhdr1.sqn = valid-sqns(v, m1, apebs[m, mkpeb(aehdr, avhdr, buf, m2, false)]).max))

User applied rule all left

And obtained the following new goals

Rule argument

pos: left 7 terms: n abort: F discard: T computed: T

Additional information

Used terms: n