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Proof step 19 from proof valid-wl-erasing-invalidate (previous step)

# apebs = # wlar, avhdr1.sqn = valid-sqns(v, m1, apebs).max, apebs[n] = mkpeb(aechdr(m5), avhdr1, buf1, m4, false), wlar[n] = wl-entry(m5, used), wlar[m] = wl-entry(m0, erasing), m < # wlar, n < # wlar, valid-peb(v, m1, mkpeb(aechdr(m5), avhdr1, buf1, m4, false)), valid-peb(v, m1, apebs[m]) ⊦ avhdr1.sqn = (valid-sqns(v, m1, apebs) \ {apebs[m].vidhdr.sqn} ).max, n = m, valid-peb(mkpeb(aehdr, avhdr, buf, m2, false))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
# apebs = # wlar, avhdr1.sqn = valid-sqns(v, m1, apebs).max, wlar[m] = wl-entry(m0, erasing), wlar[n] = wl-entry(m5, used), apebs[n] = mkpeb(aechdr(m5), avhdr1, buf1, m4, false), n < # wlar, m < # wlar, valid-peb(v, m1, apebs[m]), valid-peb(v, m1, mkpeb(aechdr(m5), avhdr1, buf1, m4, false)) ⊦ avhdr1.sqn = (valid-sqns(v, m1, apebs) -- apebs[m].vidhdr.sqn).max, n = m, valid-peb(mkpeb(aehdr, avhdr, buf, m2, false))

Rule argument

Additional information

Used simplifier rules: ⊦ bag \ {n} = bag -- n; (s)