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Proof step 18 from proof valid-wl-write-valid (previous step)

# apebs = # wlar, wlar[m] = wl-entry(m2, used), apebs[m] = mkpeb(aechdr(m2), avhdr0, buf, m3, false), m < # wlar, valid-peb(mkpeb(aechdr(m2), avhdr0, buf2, m6, false)), valid-peb(v, m5, mkpeb(aechdr(m2), avhdr0, buf2, m6, false)), valid-peb(mkpeb(aechdr(m2), avhdr0, buf, m3, false)), valid-sqns(v, m5, apebs) -- avhdr0.sqn = ∅ ∨ ¬ avhdr0.sqn < (valid-sqns(v, m5, apebs) -- avhdr0.sqn).max ⊦ ∃ v, m5. valid-peb(v, m5, mkpeb(aechdr(m2), avhdr0, buf, m3, false)) ∧ avhdr0.sqn = valid-sqns(v, m5, apebs).max

User applied rule exists right

And obtained the following new goals

Proof step 19:
# apebs = # wlar, apebs[m] = mkpeb(aechdr(m2), avhdr0, buf, m3, false), wlar[m] = wl-entry(m2, used), m < # wlar, valid-peb(mkpeb(aechdr(m2), avhdr0, buf, m3, false)), valid-peb(v, m5, mkpeb(aechdr(m2), avhdr0, buf2, m6, false)), valid-peb(mkpeb(aechdr(m2), avhdr0, buf2, m6, false)), valid-sqns(v, m5, apebs) -- avhdr0.sqn = ∅ ∨ ¬ avhdr0.sqn < (valid-sqns(v, m5, apebs) -- avhdr0.sqn).max ⊦ valid-peb(v, m5, mkpeb(aechdr(m2), avhdr0, buf, m3, false)) ∧ avhdr0.sqn = valid-sqns(v, m5, apebs).max

Rule argument

pos: right 1 terms: v, m5 abort: F discard: T computed: F

Additional information

Used terms: v, m5