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Proof step 2 from proof in-eraseq-strong-valid (previous step)

valid-eraseq-strong(apebs, to-vtbl(vols), q), eq-entry(n, v × m) ∈ q ⊦ valid-peb(v, m, apebs[n]) ∧ (v ∈ vols ∧ m < # vols[v] → apebs[n].vidhdr.sqn ≠ valid-sqns(v, m, apebs).max)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
valid-eraseq-strong(apebs, to-vtbl(vols), q), eq-entry(n, v × m) ∈ q ⊦ valid-peb(v, m, apebs[n]) ∧ (v ∈ vols ∧ m < # vols[v] → apebs[n].vidhdr.sqn ≠ valid-sqns(v, m, apebs).max)

Proof step 2 from proof in-eraseq-strong-valid (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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