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Proof step 10 from proof indices-erasing-eraseq (previous step)

wlar0[m] = wl-entry(m0, erasing), wlar1[m] = wl-entry(m1, stat), m < # wlar0, indices-erasing(wlar0, nx0), indices-erasing(wlar1, nx0), valid-eraseq(wlar1, q1), valid-eraseq(wlar0, q0), q0 ⊆ q1 ⊦ m < # wlar1 ∧ stat = erasing

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ valid-eraseq(wlar, q) ↔ (∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing)
Proof step 12:
wlar1[m] = wl-entry(m1, stat), wlar0[m] = wl-entry(m0, erasing), m < # wlar0, indices-erasing(wlar1, nx0), indices-erasing(wlar0, nx0), valid-eraseq(wlar1, q1), q0 ⊆ q1, ∀ n. n ∈ q0 ↔ n < # wlar0 ∧ wlar0[n].status = erasing ⊦ m < # wlar1 ∧ stat = erasing

Rule argument

spec: ubi-base name: valid-eraseqw seq: ⊦ valid-eraseq(wlar, q) ↔ (∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing) subst: [q, wlar] → [q0, wlar0] flags: <all paths>

Additional information

Used terms: q0, wlar0