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Proof step 29 from proof indices-erasing-eraseq (previous step)

wlar0[m] = wl-entry(m0, erasing), wlar1[m] = wl-entry(m1, stat), m < # wlar0, indices-erasing(wlar0, nx0), indices-erasing(wlar1, nx0), eq-entry(m, lref) ∈ q1, eq-entry(m, lref) ∈ q0 ⊦ ∃ eqent. eqent.pnum = m ∧ eqent ∈ q1, m < # wlar1 ∧ stat = erasing

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: eq-entry(m, lref)

Additional information

Used simplifier rules: ⊦ eq-entry(m, lref).pnum = m; (s) Used terms: eq-entry(m, lref)