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Proof step 7 from proof indices-erasing-eraseq (previous step)

wlar0[m] = wl-entry(m0, erasing), m < # wlar0, indices-erasing(wlar0, nx0), valid-eraseq(wlar0, q0), valid-eraseq(wlar1, q1), q0 ⊆ q1, ∀ wlar0, wlar1, q1, q0. indices-erasing(wlar0, nx0) ∧ valid-eraseq(wlar1, q1) ∧ valid-eraseq(wlar0, q0) ∧ q0 ⊆ q1 → indices-erasing(wlar1, nx0) ⊦ m < # wlar1 ∧ wlar1[m].status = erasing ∧ indices-erasing(wlar1, nx0)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: wlentry name: elim-02 seq: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat) subst: [wle, m, stat] → [wlar1[m], m1, stat]

Additional information

Used simplifier rules: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat); (elim) Used terms: wlar1[m], m1, stat