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Proof step 5 from proof ubi-io-initial-valid-sqns-h (previous step)

n0 < # apebs, ubi-io-initial(apebs), ∀ apebs, v, m. ubi-io-initial(apebs) ∧ n0 ≤ # apebs → valid-sqns(v, m, apebs, n0) = ∅ ⊦ valid-sqns(v, m, apebs, n0) ∪ (valid-peb(v, m, apebs[n0]) ⊃ {apebs[n0].vidhdr.sqn} ;∅) = ∅

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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