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Proof step 18 from proof valid-eraseq-map-indices-nostatchange (previous step)

n ∈ q ↔ stat0 = erasing, wlar[n] = wl-entry(m0, stat0), f(wl-entry(m0, stat0)) = wl-entry(m, stat), n < # wlar, valid-indices(wlar, nx), n ∈ nx, ∀ wle. f(wle).status = wle.status ⊦ stat0 = erasing ↔ stat = erasing, dups(nx)

User applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: wl-entry(m0, stat0) abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ wl-entry(m, stat).status = stat; (s) Used terms: wl-entry(m0, stat0)