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Proof step 7 from proof valid-eraseq-map-indices-nostatchange (previous step)

valid-indices(wlar, nx), ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing, ∀ wle. f(wle).status = wle.status ⊦ dups(nx), ∀ n. n ∈ q ↔ n < # wlar.mapIndices(nx, f) ∧ wlar.mapIndices(nx, f)[n].status = erasing

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
valid-indices(wlar, nx), ∀ wle. f(wle).status = wle.status, ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ n ∈ q ↔ n < # wlar.mapIndices(nx, f) ∧ wlar.mapIndices(nx, f)[n].status = erasing, dups(nx)

Proof step 7 from proof valid-eraseq-map-indices-nostatchange (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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