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Proof step 9 from proof valid-eraseq-map-indices-nostatchange (previous step)

wlar.mapIndices(nx, f)[n] = wl-entry(m, stat), valid-indices(wlar, nx), ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing, ∀ wle. f(wle).status = wle.status ⊦ n ∈ q ↔ n < # wlar.mapIndices(nx, f) ∧ stat = erasing, dups(nx)

User applied rule all left

And obtained the following new goals

Proof step 10:
n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing, wlar.mapIndices(nx, f)[n] = wl-entry(m, stat), valid-indices(wlar, nx), ∀ wle. f(wle).status = wle.status ⊦ n ∈ q ↔ n < # wlar.mapIndices(nx, f) ∧ stat = erasing, dups(nx)

Rule argument

pos: left 3 terms: n abort: F discard: T computed: T

Additional information

Used terms: n