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Proof step 6 from proof valid-eraseq-strong-imp-q (previous step)

eqent = eq-entry(m0, lref), m0 < # apebs, valid-eraseq-strong(apebs, vtbl, q0), (∃ apebs, vtbl. valid-eraseq-strong(apebs, vtbl, q0)) → valid-eraseq(q0), ∀ v, m. (valid-peb(v, m, apebs[m0]) ↔ lref = v × m) ∧ (lref = v × m ∧ v ∈ vtbl ∧ m < vtbl[v] → apebs[m0].vidhdr.sqn ≠ valid-sqns(v, m, apebs).max) ⊦ valid-eraseq(eqent ' + q0), m0 ∈ q0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
m0 < # apebs, valid-eraseq-strong(apebs, vtbl, q0), (∃ apebs, vtbl. valid-eraseq-strong(apebs, vtbl, q0)) → valid-eraseq(q0), ∀ v, m. (valid-peb(v, m, apebs[m0]) ↔ lref = v × m) ∧ (lref = v × m ∧ v ∈ vtbl ∧ m < vtbl[v] → apebs[m0].vidhdr.sqn ≠ valid-sqns(v, m, apebs).max) ⊦ valid-eraseq(eq-entry(m0, lref) ' + q0), m0 ∈ q0

Proof step 6 from proof valid-eraseq-strong-imp-q (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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