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Proof step 2 from proof valid-eraseq-strong-notinvols (previous step)

n < # apebs, valid-eraseq-strong(apebs, vtbl, q), valid-peb(v, m, apebs[n]), ¬ v ∈ vtbl ∨ ¬ m < vtbl[v] ⊦ valid-eraseq-strong(apebs, vtbl, q + eq-entry(n, v × m) '), n ∈ q

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n < # apebs, valid-eraseq-strong(apebs, vtbl, q), valid-peb(v, m, apebs[n]), ¬ v ∈ vtbl ∨ ¬ m < vtbl[v] ⊦ valid-eraseq-strong(apebs, vtbl, q + eq-entry(n, v × m) '), n ∈ q

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic