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Proof step 8 from proof valid-eraseq-stronger-next-append-lref (previous step)

apebs[m] = mkpeb(aehdr, avhdr, buf, m0, boolvar), subarray(apebs, 0, m + 1)[m] = mkpeb(aehdr0, avhdr0, buf0, m1, boolvar0), m < # apebs ⊦ valid-peb(v, n, subarray(apebs, 0, m + 1)[m]) ∧ avhdr0.sqn ≠ (valid-sqns(v, n, apebs, m) ∪ (valid-peb(v, n, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊃ {avhdr.sqn} ;∅)).max ↔ valid-peb(v, n, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ∧ valid-sqns(v, n, apebs, m) ≠ ∅ ∧ avhdr.sqn < valid-sqns(v, n, apebs, m).max

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
subarray(apebs, 0, m + 1)[m] = mkpeb(aehdr0, avhdr0, buf0, m1, boolvar0), apebs[m] = mkpeb(aehdr, avhdr, buf, m0, boolvar), m < # apebs ⊦ valid-peb(v, n, mkpeb(aehdr0, avhdr0, buf0, m1, boolvar0)) ∧ avhdr0.sqn ≠ (valid-sqns(v, n, apebs, m) ∪ (valid-peb(v, n, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊃ {avhdr.sqn} ;∅)).max ↔ valid-peb(v, n, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ∧ valid-sqns(v, n, apebs, m) ≠ ∅ ∧ avhdr.sqn < valid-sqns(v, n, apebs, m).max

Proof step 8 from proof valid-eraseq-stronger-next-append-lref (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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