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Proof step 26 from proof valid-eraseq-stronger-next (previous step)

avhdr.sqn = avhdr0.sqn, apebs[m1] = mkpeb(aehdr, avhdr, buf, m2, boolvar), apebs[m] = mkpeb(aehdr0, avhdr0, buf0, m3, boolvar0), valid-sqns(v, m0, apebs, m) = ∅, m1 < # apebs, m < # apebs, m1 < m, m1 + 1 < # apebs, valid-eraseq-stronger(subarray(apebs, 0, m), q0), valid-eraseq-stronger(subarray(apebs, 0, m + 1), q0), valid-peb(v, m0, mkpeb(aehdr, avhdr, buf, m2, boolvar)), valid-peb(v, m0, mkpeb(aehdr0, avhdr0, buf0, m3, boolvar0)), ∀ m, apebs. m < # apebs ∧ valid-eraseq-stronger(subarray(apebs, 0, m), q0) → valid-eraseq-stronger(subarray(apebs, 0, m + 1), q0) ⊦ avhdr.sqn = valid-sqns(v, m0, apebs, m).max, m1 ∈ q0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
avhdr.sqn = avhdr0.sqn, apebs[m] = mkpeb(aehdr0, avhdr0, buf0, m3, boolvar0), apebs[m1] = mkpeb(aehdr, avhdr, buf, m2, boolvar), valid-sqns(v, m0, apebs, m) = ∅, m1 + 1 < # apebs, m1 < m, m < # apebs, m1 < # apebs, valid-eraseq-stronger(subarray(apebs, 0, m + 1), q0), valid-eraseq-stronger(subarray(apebs, 0, m), q0), valid-peb(v, m0, mkpeb(aehdr0, avhdr0, buf0, m3, boolvar0)), valid-peb(v, m0, mkpeb(aehdr, avhdr, buf, m2, boolvar)), ∀ m, apebs. m < # apebs ∧ valid-eraseq-stronger(subarray(apebs, 0, m), q0) → valid-eraseq-stronger(subarray(apebs, 0, m + 1), q0) ⊦ avhdr0.sqn = ∅.max, m1 ∈ q0

Proof step 26 from proof valid-eraseq-stronger-next (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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