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Proof step 30 from proof valid-eraseq-stronger-next (previous step)

avhdr.sqn = (avhdr0.sqn < valid-sqns(v, m0, apebs, m).max ⊃ valid-sqns(v, m0, apebs, m).max;avhdr0.sqn), apebs[m] = mkpeb(aehdr0, avhdr0, buf0, m3, boolvar0), apebs[m1] = mkpeb(aehdr, avhdr, buf, m2, boolvar), m1 + 1 < # apebs, m1 < m, m < # apebs, m1 < # apebs, valid-eraseq-stronger(subarray(apebs, 0, m + 1), q0), valid-eraseq-stronger(subarray(apebs, 0, m), q0), valid-peb(v, m0, mkpeb(aehdr0, avhdr0, buf0, m3, boolvar0)), valid-peb(v, m0, mkpeb(aehdr, avhdr, buf, m2, boolvar)), ∀ m, apebs. m < # apebs ∧ valid-eraseq-stronger(subarray(apebs, 0, m), q0) → valid-eraseq-stronger(subarray(apebs, 0, m + 1), q0) ⊦ avhdr.sqn = valid-sqns(v, m0, apebs, m).max, valid-sqns(v, m0, apebs, m) = ∅, m1 ∈ q0

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 1

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