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Proof step 2 from proof valid-eraseq-stronger-no-maxsqnum (previous step)

apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max, n < # apebs, valid-eraseq-stronger(apebs, q), valid-peb(v, m, apebs[n]), n ∈ q ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max, n < # apebs, valid-eraseq-stronger(apebs, q), valid-peb(v, m, apebs[n]), n ∈ q ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic