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Proof step 4 from proof valid-eraseq-stronger-prev-append-lref (previous step)

apebs[m] = mkpeb(aehdr, avhdr, buf, m1, boolvar), m0 + 1 < # apebs, m < # apebs, m0 < m, valid-sqns(v, n, apebs, m).max < avhdr.sqn, m0 < # apebs, valid-eraseq-stronger(subarray(apebs, 0, m), q), valid-peb(v, n, apebs[m0]), valid-peb(v, n, apebs[m]) ⊦ valid-eraseq-stronger(subarray(apebs, 0, m + 1), q + eq-entry(m0, v × n) '), m0 ∈ q

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
apebs[m] = mkpeb(aehdr, avhdr, buf, m1, boolvar), m0 + 1 < # apebs, m < # apebs, m0 < m, valid-sqns(v, n, apebs, m).max < avhdr.sqn, m0 < # apebs, valid-eraseq-stronger(subarray(apebs, 0, m), q), valid-peb(v, n, apebs[m0]), valid-peb(v, n, mkpeb(aehdr, avhdr, buf, m1, boolvar)) ⊦ valid-eraseq-stronger(subarray(apebs, 0, m + 1), q + eq-entry(m0, v × n) '), m0 ∈ q

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic