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Proof step 16 from proof valid-recs-in-nonempty-sqns (
previous step
)
n0 < n1, n1 ≤ # apebs ⊦ valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ∧ apebs[n0] = mkpeb(aehdr, avhdr, buf, m0, boolvar) → avhdr.sqn ∈ valid-sqns(v, m, apebs, n1)
A spec-lemma