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Proof step 9 from proof valid-recs-next-add (previous step)

# wlar = # apebs, v0 × m6 ∈ recs ∧ recs[v0 × m6].pnum = m5 ↔ wlar[m5].status = used ∧ m5 < m ∧ apebs[m5].vidhdr.vol = (v0 × m6).vol ∧ apebs[m5].vidhdr.leb = (v0 × m6).leb, subarray(wlar[m, wl-entry(m3, used)], 0, m + 1)[m5] = wl-entry(m10, stat), recs[v × n, recovery-entry(m, m0)][v0 × m6] = recovery-entry(m7, m8), apebs[m] = mkpeb(aehdr, avidhdr(v, n, m0, m1, m4), buf, m2, boolvar), subarray(apebs, 0, m + 1)[m5] = mkpeb(aehdr0, avhdr, buf0, m9, boolvar0), m < # apebs ⊦ v0 × m6 ∈ recs[v × n, recovery-entry(m, m0)] ∧ m7 = m5 ↔ stat = used ∧ ¬ m < m5 ∧ avhdr.vol = v0 ∧ avhdr.leb = m6, v × n ∈ recs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
# wlar = # apebs, v0 × m6 ∈ recs ∧ recs[v0 × m6].pnum = m5 ↔ wlar[m5].status = used ∧ m5 < m ∧ apebs[m5].vidhdr.vol = v0 ∧ apebs[m5].vidhdr.leb = m6, subarray(apebs, 0, m + 1)[m5] = mkpeb(aehdr0, avhdr, buf0, m9, boolvar0), apebs[m] = mkpeb(aehdr, avidhdr(v, n, m0, m1, m4), buf, m2, boolvar), recs[v × n, recovery-entry(m, m0)][v0 × m6] = recovery-entry(m7, m8), subarray(wlar[m, wl-entry(m3, used)], 0, m + 1)[m5] = wl-entry(m10, stat), m < # apebs ⊦ v0 × m6 ∈ recs[v × n, recovery-entry(m, m0)] ∧ m7 = m5 ↔ stat = used ∧ ¬ m < m5 ∧ avhdr.vol = v0 ∧ avhdr.leb = m6, v × n ∈ recs

Rule argument

Additional information

Used simplifier rules: ⊦ (v × m).leb = m; (s)% ⊦ (v × m).vol = v; (s)