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Proof step 12 from proof valid-recs-sqns-update (previous step)

apebs[m0] = mkpeb(aehdr, avhdr, buf, m2, boolvar), apebs[m1] = mkpeb(aehdr0, avhdr0, buf0, m4, boolvar0), recs[ladr] = recovery-entry(m1, m3), m0 < # apebs, ladr ∈ recs, ∀ ladr. ladr ∈ recs → recs[ladr].pnum < # apebs ∧ apebs[recs[ladr].pnum].vidhdr.sqn = recs[ladr].sqn ⊦ ladr = v × m, m1 < # apebs ∧ avhdr0.sqn = m3

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: ladr

Additional information

Used simplifier rules: ⊦ recovery-entry(m, m0).pnum = m; (s)% ⊦ recovery-entry(m, m0).sqn = m0; (s)% ⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).vidhdr = avhdr; (s) Used terms: ladr