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Proof step 2 from proof valid-recs-sqns-update (previous step)

valid-recs-sqns(apebs, recs) ⊦ valid-recs-sqns(apebs, recs[v × m, recovery-entry(m0, m1)]) ↔ m0 < # apebs ∧ apebs[m0].vidhdr.sqn = m1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ ladr. ladr ∈ recs → recs[ladr].pnum < # apebs ∧ apebs[recs[ladr].pnum].vidhdr.sqn = recs[ladr].sqn ⊦ (∀ ladr. ladr ∈ recs[v × m, recovery-entry(m0, m1)] → recs[v × m, recovery-entry(m0, m1)][ladr].pnum < # apebs ∧ apebs[recs[v × m, recovery-entry(m0, m1)][ladr].pnum].vidhdr.sqn = recs[v × m, recovery-entry(m0, m1)][ladr].sqn) ↔ m0 < # apebs ∧ apebs[m0].vidhdr.sqn = m1

Rule argument

Additional information

Used simplifier rules: valid-recs-sqns: ⊦ valid-recs-sqns(apebs, recs) ↔ (∀ ladr. ladr ∈ recs → recs[ladr].pnum < # apebs ∧ apebs[recs[ladr].pnum].vidhdr.sqn = recs[ladr].sqn);