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Proof step 6 from proof valid-recs-sqns-update (previous step)

apebs[m0] = mkpeb(aehdr, avhdr, buf, m2, boolvar), ∀ ladr. ladr ∈ recs[v × m, recovery-entry(m0, m1)] → recs[v × m, recovery-entry(m0, m1)][ladr].pnum < # apebs ∧ apebs[recs[v × m, recovery-entry(m0, m1)][ladr].pnum].vidhdr.sqn = recs[v × m, recovery-entry(m0, m1)][ladr].sqn, ∀ ladr. ladr ∈ recs → recs[ladr].pnum < # apebs ∧ apebs[recs[ladr].pnum].vidhdr.sqn = recs[ladr].sqn ⊦ m0 < # apebs ∧ avhdr.sqn = m1

User applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: v × m abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ ladr ∈ recs[ladr, rec]; (s)% ⊦ recs[ladr, rec][ladr] = rec; (s)% ⊦ recovery-entry(m, m0).pnum = m; (s)% ⊦ recovery-entry(m, m0).sqn = m0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)% ⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).vidhdr = avhdr; (s) Used terms: v × m