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Proof step 7 from proof valid-recs-sqns-update (previous step)

avhdr.sqn = m1, apebs[m0] = mkpeb(aehdr, avhdr, buf, m2, boolvar), m0 < # apebs, ∀ ladr. ladr ∈ recs → recs[ladr].pnum < # apebs ∧ apebs[recs[ladr].pnum].vidhdr.sqn = recs[ladr].sqn ⊦ ∀ ladr. ladr ∈ recs[v × m, recovery-entry(m0, m1)] → recs[v × m, recovery-entry(m0, m1)][ladr].pnum < # apebs ∧ apebs[recs[v × m, recovery-entry(m0, m1)][ladr].pnum].vidhdr.sqn = recs[v × m, recovery-entry(m0, m1)][ladr].sqn

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
apebs[m0] = mkpeb(aehdr, avhdr, buf, m2, boolvar), m0 < # apebs, ladr ∈ recs[v × m, recovery-entry(m0, avhdr.sqn)], ∀ ladr. ladr ∈ recs → recs[ladr].pnum < # apebs ∧ apebs[recs[ladr].pnum].vidhdr.sqn = recs[ladr].sqn ⊦ recs[v × m, recovery-entry(m0, avhdr.sqn)][ladr].pnum < # apebs ∧ apebs[recs[v × m, recovery-entry(m0, avhdr.sqn)][ladr].pnum].vidhdr.sqn = recs[v × m, recovery-entry(m0, avhdr.sqn)][ladr].sqn

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic