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Proof step 1 from proof vols-le-trans (conclusion)
⊦ vols0 ⊆ vols1 ∧ vols1 ⊆ vols2 → vols0 ⊆ vols2
System applied rule normalize
And obtained the following new goals
Proof step 2
:
vols0 ⊆ vols1, vols1 ⊆ vols2 ⊦ vols0 ⊆ vols2
Rule argument
Additional information