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Proof step 3 from proof ecs-empty (previous step)

⊦ ecs(wlar, # wlar) = ∅ ↔ # wlar = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ n ≤ # wlar → (ecs(wlar, n) = ∅ ↔ n = 0)

Rule argument

spec: <toplevel> name: ecs-n-empty seq: ⊦ n ≤ # wlar → (ecs(wlar, n) = ∅ ↔ n = 0) subst: [n, wlar] → [# wlar, wlar] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ ¬ n < n; (s) Used terms: # wlar, wlar