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Proof step 15 from proof in-ecs-n (
previous step
)
wlar[n0] = wl-entry(m0, stat), n0 < # wlar, ∀ wlar, m. n0 ≤ # wlar → (m ∈ ecs(wlar, n0) ↔ (∃ n1. n1 < n0 ∧ wlar[n1].ec = m)) ⊦ ∃ n. ¬ n0 < n ∧ wlar[n].ec = m0
User applied rule exists right
And closed the goal!
Rule argument
pos: right 1 terms: n0 abort: F discard: T computed: T
Additional information
Used simplifier rules: ⊦ ¬ n < n; (s)% ⊦ wl-entry(m, stat).ec = m; (s) Used terms: n0