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Proof step 2 from proof sum-of-differences-in (previous step)

m ∈ bag ⊦ sum-of-differences(n, bag) ≥ n - m

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
sum-of-differences(n, bag) < n - m, m ∈ bag ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ n ≥ m ↔ m ≤ n; (s)