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Proof step 8 from proof sum-of-differences-in (previous step)

(n - vtblpnum) + sum-of-differences(n, bag0) < n - m, m ∈ bag0, ∀ n0, m0. ¬ sum-of-differences(n0, bag0) < n0 - m0 ∨ ¬ m0 ∈ bag0 ⊦ m = vtblpnum

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: n, m abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ ¬ m < n → ¬ m + m0 < n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used terms: n, m