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Proof step 12 from proof sum-of-differences-rem (previous step)

∀ n, m. sum-of-differences(n, bag0 -- m) = (m ∈ bag0 ⊃ sum-of-differences(n, bag0) - (n - m);sum-of-differences(n, bag0)) ⊦ sum-of-differences(n, bag0 -- m) = sum-of-differences(n, bag0), vtblpnum = m, m ∈ bag0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: n, m

Additional information

Used terms: n, m