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Proof step 1 from proof wlar-erase-worker-helper (conclusion)

wlar0 = wlar, n < # wlar ⊦ [ubi_erase_worker_helper#(n; wlar, apebs; err)] ∃ m, stat. m ≠ 0 ∧ m ≤ UBI_ERASE_RETRIES + 1 ∧ wlar = wlar0[n, wl-entry(wlar0[n].ec + m, stat)]

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 2:
wlar0[n] = wl-entry(m0, stat0), wlar0 = wlar, n < # wlar ⊦ [ubi_erase_worker_helper#(n; wlar, apebs; err)] ∃ m, stat. m ≠ 0 ∧ m ≤ UBI_ERASE_RETRIES + 1 ∧ wlar = wlar0[n, wl-entry(m0 + m, stat)]

Rule argument

spec: wlentry name: elim-02 seq: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat) subst: [wle, m, stat] → [wlar0[n], m0, stat0]

Additional information

Used simplifier rules: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat); (elim) Used terms: wlar0[n], m0, stat0