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Proof step 150 from proof wlar-erase-worker-helper (previous step)

wlar[n] = wl-entry(m0, stat0), apebs0[n] = mkpeb(aehdr, avhdr, buf, m1, false), n < # apebs0, n < # wlar, ubi-io-peb-inv(apeb), ⌊err0⌋ , ¬ apeb.bad, ¬ apeb.vidhdr.valid? ⊦ [debug#("ubi: erase of PEB " + n.toString + " failed"); vtblpnum1 := 1; wlar1 := wlar[n, wlar[n].ec:= (wlar[n].ec + 1)]; vtblpnum0 := n; apebs := apebs0[n, apeb]; while err0 ≠ ESUCCESS ∧ vtblpnum1 ≤ UBI_ERASE_RETRIES do {wlar1[vtblpnum0].ec := wlar1[vtblpnum0].ec + 1; aubi_io_sync_erase#(vtblpnum0; apebs; err0); if err0 = ESUCCESS then aubi_io_write_echdr#(vtblpnum0, aechdr(wlar1[vtblpnum0].ec); apebs; err0) else debug#("ubi: erase of PEB " + vtblpnum0.toString + " failed"); vtblpnum1 := vtblpnum1 + 1}; if err0 = ESUCCESS then wlar1[vtblpnum0] := wl-entry(wlar1[vtblpnum0].ec, free) else {aubi_io_markbad#(vtblpnum0; apebs; err0); if err0 = ESUCCESS then wlar1[vtblpnum0] := wl-entry(wlar1[vtblpnum0].ec, erroneous) else debug#("ubi: marking PEB " + vtblpnum0.toString + " as bad failed")}] ∃ m, stat. m ≠ 0 ∧ m ≤ UBI_ERASE_RETRIES + 1 ∧ wlar1 = wlar[n, wl-entry(m0 + m, stat)]

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: apeb name: elim seq: ⊦ ( ( (aehdr = apeb.echdr ∧ avhdr = apeb.vidhdr) ∧ buf = apeb.data) ∧ m = apeb.fill) ∧ (boolvar ↔ apeb.bad) ↔ apeb = mkpeb(aehdr, avhdr, buf, m, boolvar) subst: [apeb, aehdr, avhdr, buf, m, boolvar] → [apeb, aehdr0, avhdr0, buf0, m2, boolvar]

Additional information

Used simplifier rules: ⊦ ( ((aehdr = apeb.echdr ∧ avhdr = apeb.vidhdr) ∧ buf = apeb.data) ∧ m = apeb.fill) ∧ (boolvar ↔ apeb.bad) ↔ apeb = mkpeb(aehdr, avhdr, buf, m, boolvar); (elim) Used terms: apeb, aehdr0, avhdr0, buf0, m2, boolvar