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Proof step 181 from proof wlar-erase-worker-helper (previous step)

wlar[n] = wl-entry(m0, stat0), apebs0[n] = mkpeb(aehdr2, avhdr, buf, m1, false), apebs1[n] = mkpeb(aehdr1, avhdr1, buf1, m, false), n < # wlar, n < # apebs0, n < # apebs1, ubi-io-peb-inv(mkpeb(aehdr0, avhdr0, buf0, m2, false)), vtblpnum1 ≤ UBI_ERASE_RETRIES, vtblpnum1 ≤ UBI_ERASE_RETRIES + 1, ⌊err2⌋ ⊦ [choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err = ESUCCESS then apebs := apebs1[n, mkpeb(empty, empty, mkempbuf(LEB_SIZE), 0, false)] [n, apebs1[n, mkpeb(empty, empty, mkempbuf(LEB_SIZE), 0, false)][n] .echdr:= aechdr (wlar[n, wlar[n, wl-entry(wlar[n].ec + vtblpnum1, stat)][n].ec:= (wlar[n, wl-entry(wlar[n].ec + vtblpnum1, stat)][n].ec + 1)][n] .ec) ] else {vtblpnum := n; apebs := apebs1[n, mkpeb(empty, empty, mkempbuf(LEB_SIZE), 0, false)]; choose aehdr with ¬ aehdr.valid? in apebs[vtblpnum].echdr := aehdr}; vtblpnum := vtblpnum1 + 1] ( vtblpnum ≠ 0 ∧ vtblpnum ≤ UBI_ERASE_RETRIES + 1 ∧ (∃ stat1. wlar[n, wl-entry((wlar[n].ec + vtblpnum1) + 1, stat)] = wlar[n, wl-entry(wlar[n].ec + vtblpnum, stat1)])), err1 = ESUCCESS, vtblpnum1 = 0, avhdr0.valid?

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

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