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Proof step 31 from proof wlar-erase-worker-helper (previous step)

wlar[n] = wl-entry(m0, stat0), apebs0[n] = mkpeb(aehdr0, avhdr, buf, m1, false), apebs = apebs0[n, mkpeb(empty, empty, mkempbuf(LEB_SIZE), 0, false)], err = err0, n < # wlar, n < # apebs0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ [if err = ESUCCESS then apebs[n].echdr := aechdr(wlar[n, wlar[n].ec:= (wlar[n].ec + 1)][n].ec) else {vtblpnum := n; choose aehdr with ¬ aehdr.valid? in apebs[vtblpnum].echdr := aehdr}; vtblpnum1 := 1; wlar1 := wlar[n, wlar[n].ec:= (wlar[n].ec + 1)]; vtblpnum0 := n; err1 := err; while err1 ≠ ESUCCESS ∧ vtblpnum1 ≤ UBI_ERASE_RETRIES do {wlar1[vtblpnum0].ec := wlar1[vtblpnum0].ec + 1; aubi_io_sync_erase#(vtblpnum0; apebs; err1); if err1 = ESUCCESS then aubi_io_write_echdr#(vtblpnum0, aechdr(wlar1[vtblpnum0].ec); apebs; err1) else debug#("ubi: erase of PEB " + vtblpnum0.toString + " failed"); vtblpnum1 := vtblpnum1 + 1}; if err1 = ESUCCESS then wlar1[vtblpnum0] := wl-entry(wlar1[vtblpnum0].ec, free) else {aubi_io_markbad#(vtblpnum0; apebs; err1); if err1 = ESUCCESS then wlar1[vtblpnum0] := wl-entry(wlar1[vtblpnum0].ec, erroneous) else debug#("ubi: marking PEB " + vtblpnum0.toString + " as bad failed")}] ∃ m, stat. m ≠ 0 ∧ m ≤ UBI_ERASE_RETRIES + 1 ∧ wlar1 = wlar[n, wl-entry(m0 + m, stat)]

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

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