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Proof step 9 from proof wlar-erase-worker-helper (previous step)

wlar[n] = wl-entry(m0, stat0), err = EIO, vtblpnum = 0, vtblpnum0 = n, wlar0 = wlar, n < # wlar ⊦ [wlar[vtblpnum0].ec := wlar[vtblpnum0].ec + 1; aubi_io_sync_erase#(vtblpnum0; apebs; err); if err = ESUCCESS then aubi_io_write_echdr#(vtblpnum0, aechdr(wlar[vtblpnum0].ec); apebs; err) else debug#("ubi: erase of PEB " + vtblpnum0.toString + " failed"); vtblpnum := vtblpnum + 1; while err ≠ ESUCCESS ∧ vtblpnum ≤ UBI_ERASE_RETRIES do {wlar[vtblpnum0].ec := wlar[vtblpnum0].ec + 1; aubi_io_sync_erase#(vtblpnum0; apebs; err); if err = ESUCCESS then aubi_io_write_echdr#(vtblpnum0, aechdr(wlar[vtblpnum0].ec); apebs; err) else debug#("ubi: erase of PEB " + vtblpnum0.toString + " failed"); vtblpnum := vtblpnum + 1}; if err = ESUCCESS then wlar[vtblpnum0] := wl-entry(wlar[vtblpnum0].ec, free) else {aubi_io_markbad#(vtblpnum0; apebs; err); if err = ESUCCESS then wlar[vtblpnum0] := wl-entry(wlar[vtblpnum0].ec, erroneous) else debug#("ubi: marking PEB " + vtblpnum0.toString + " as bad failed")}] ∃ m, stat. m ≠ 0 ∧ m ≤ UBI_ERASE_RETRIES + 1 ∧ wlar = wlar0[n, wl-entry(m0 + m, stat)]

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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