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Proof step 23 from proof initialization (previous step)

⌊err1⌋ ⊦ ⟨choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0; if err = ESUCCESS then avols := ∅ else avols := ?⟩ (avols1 = avols ∧ err1 = err)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information