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Proof step 27 from proof initialization (previous step)

err = err1, ⌊err1⌋ ⊦ ⟨if err = ESUCCESS then avols := ∅ else avols := ?⟩ (avols1 = avols ∧ err1 = err)

Heuristic symbolic execution applied rule if negative right

And obtained the following new goals

Proof step 28:
err = err1, ⌊err1⌋ ⊦ ⟨avols := ?⟩ (avols1 = avols ∧ err1 = err)

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ ⌊err⌋ → err ≠ ESUCCESS; (s)