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Proof step 10 from proof lf-mapped-not-bad (previous step)

wlar[n].status = used, apebs[n] = mkpeb(aehdr, avhdr, buf, m0, true), vols[v0][m1] = ⌜n⌝ , avhdr = avidhdr(v0, m1, m2, m3, m4), avhdr.valid?, m1 < # vols[v0], n < # wlar, n < # apebs, v0 ∈ vols, ∀ n. n < # wlar → (wlar[n].status = erroneous ↔ apebs[n].bad) ∧ (wlar[n].status = free → apebs[n].vidhdr = empty) ∧ (wlar[n].status ≠ erroneous ∧ wlar[n].status ≠ erasing → apebs[n].echdr = aechdr(wlar[n].ec)) ∧ (wlar[n].status = used → (∃ v, m. valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max)), ∀ v, m, n. vols[v][m] = ⌜n⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n].status = used ∧ n < # apebs ∧ n < # wlar ∧ apebs[n].vidhdr.valid? ∧ apebs[n].vidhdr.vol = v ∧ apebs[n].vidhdr.leb = m ∧ n ≠ n0 ⊦ n = n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
wlar[n].status = used, apebs[n] = mkpeb(aehdr, avidhdr(v0, m1, m2, m3, m4), buf, m0, true), vols[v0][m1] = ⌜n⌝ , m1 < # vols[v0], n < # wlar, n < # apebs, v0 ∈ vols, ∀ n. n < # wlar → (wlar[n].status = erroneous ↔ apebs[n].bad) ∧ (wlar[n].status = free → apebs[n].vidhdr = empty) ∧ (wlar[n].status ≠ erroneous ∧ wlar[n].status ≠ erasing → apebs[n].echdr = aechdr(wlar[n].ec)) ∧ (wlar[n].status = used → (∃ v, m. valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max)), ∀ v, m, n. vols[v][m] = ⌜n⌝ ∧ v ∈ vols ∧ m < # vols[v] ↔ wlar[n].status = used ∧ n < # apebs ∧ n < # wlar ∧ apebs[n].vidhdr.valid? ∧ apebs[n].vidhdr.vol = v ∧ apebs[n].vidhdr.leb = m ∧ n ≠ n0 ⊦ n = n0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ avidhdr(v, m, m0, m1, m2).valid?; (s)