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Proof step 13 from proof rangeeq-emptyleb-datasize (previous step)

# buf = n0 + n1, n2 < n0 + n1, n1 ≤ LEB_SIZE, n0 ≤ n2, ∀ n. n < n1 → buf[n0 + n] = empty, ∀ buf0, n, n3. # buf0 ≠ n + n3 ∨ ¬ n < datasize(buf0, n2) ∨ ¬ range=(buf0, n, emptyleb, 0, n3) ∨ ¬ n2 ≤ n + n3 ⊦ buf[n2] = empty, n1 = 0

User applied rule all left

And obtained the following new goals

Proof step 14:
# buf = n0 + n1, n2 < n0 + n1, n0 ≤ n2, n1 ≤ LEB_SIZE, n2 - n0 < n1 → buf[n0 + (n2 - n0)] = empty, ∀ buf0, n, n3. # buf0 ≠ n + n3 ∨ ¬ n < datasize(buf0, n2) ∨ ¬ range=(buf0, n, emptyleb, 0, n3) ∨ ¬ n2 ≤ n + n3 ⊦ buf[n2] = empty, n1 = 0

Rule argument

pos: left 5 terms: n2 - n0 abort: F discard: T computed: F

Additional information

Used terms: n2 - n0