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Proof step 8 from proof rangeeq-emptyleb-datasize (previous step)

# buf = n0 + n1, buf[n2] = empty, n2 < n0 + n1, n0 < datasize(buf, n2), range=(buf, n0, emptyleb, 0, n1), ∀ buf0, n, n3. # buf0 ≠ n + n3 ∨ ¬ n < datasize(buf0, n2) ∨ ¬ range=(buf0, n, emptyleb, 0, n3) ∨ ¬ n2 ≤ n + n3 ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: buf, n0, n1

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n; (s) Used terms: buf, n0, n1