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Proof step 11 from proof recovery (previous step)

# apebs0 = # wlar0, # wlar = # wlar0, abs(avols0, apebs0, vols, q), bflipset-cons(bflipset, wlar), bflipset-cons(bflipset0, wlar0), ebm-cons(avols0), is-max(apebs0, vols0, wlar0, q0, bflipset0, vtblpnum3, sqnum), ubi-io-inv(apebs0), unique-sqns(apebs0), valid-ebatbl(apebs0, wlar, vols, vtblpnum), valid-ebatbl(apebs0, wlar0, vols0, vtblpnum3), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs0, q), valid-eraseq(q0), valid-eraseq(wlar0, q0), valid-eraseq(apebs0, q0), valid-global-sqn(apebs0, vtblpnum0), valid-global-sqn(apebs0, sqnum), valid-vtbl(apebs0, vols, wlar, vtblpnum), valid-vtbl(apebs0, vols0, wlar0, vtblpnum3), valid-wl(apebs0, wlar), valid-wl(apebs0, wlar0), q0.lebrefs ⊆ q.lebrefs, vols ⊆ vols0, vols0⌈vols, q⌉ ⊦ avols0 ⊆ absf(avols0, apebs0, vols0, q0) ∧ ebm-cons(absf(avols0, apebs0, vols0, q0)) ∧ ⟨avols := absf(avols0, apebs0, vols0, q0); ebm_recover#(; avols; err0)⟩ (abs(avols, apebs0, vols0, q0) ∧ ESUCCESS = err0), VTBL_VOLID ∈ vols0, VTBL_VOLID ∈ vols

Heuristic dl case distinction applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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