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Proof step 143 from proof recovery (previous step)

# apebs0 = # wlar0, # wlar = # wlar0, apebs0[vols0[v][m].pnum] = mkpeb(aehdr, avhdr, buf, m0, boolvar), abs(avols0, apebs0, vols, q), bflipset-cons(bflipset, wlar), bflipset-cons(bflipset0, wlar0), ebm-cons(avols0), is-max(apebs0, vols0, wlar0, q0, bflipset0, vtblpnum3, sqnum), ubi-io-inv(apebs0), unique-sqns(apebs0), valid-ebatbl(apebs0, wlar, vols, vtblpnum), valid-ebatbl(apebs0, wlar0, vols0, vtblpnum3), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs0, q), valid-eraseq(q0), valid-eraseq(wlar0, q0), valid-eraseq(apebs0, q0), valid-global-sqn(apebs0, vtblpnum0), valid-global-sqn(apebs0, sqnum), valid-vtbl(apebs0, vols, wlar, vtblpnum), valid-vtbl(apebs0, vols0, wlar0, vtblpnum3), valid-wl(apebs0, wlar), valid-wl(apebs0, wlar0), q0.lebrefs ⊆ q.lebrefs, vols ⊆ vols0, vols0⌈vols, q⌉ ⊦ VTBL_VOLID ∈ vols0, VTBL_VOLID ∈ vols, (v ∈ vols0 ↔ v ∈ vols0) ∧ ( v ∈ vols0 → # vols0[v] = # absf(avols0, apebs0, vols0, q0)[v] ∧ ( m < # vols0[v] → (vols0[v][m] = unmapped → ¬ absf(avols0, apebs0, vols0, q0)[v][m].mapped?) ∧ ( vols0[v][m] ≠ unmapped → absf(avols0, apebs0, vols0, q0)[v][m].mapped? ∧ absf(avols0, apebs0, vols0, q0)[v][m].data = buf ∧ m0 ≤ absf(avols0, apebs0, vols0, q0)[v][m].fill) ∧ (absf(avols0, apebs0, vols0, q0)[v][m] = erased → ¬ v × m ∈ q0)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information