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Proof step 17 from proof recovery (previous step)

⊦ vols0 ⊆ vols1 ↔ (∀ v. (v ∈ vols0 ↔ v ∈ vols1) ∧ (v ∈ vols0 → # vols0[v] = # vols1[v] ∧ (∀ m. m < # vols0[v] ∧ vols0[v][m] ≠ unmapped → vols0[v][m] = vols1[v][m])))

A spec-lemma