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Proof step 7 from proof recovery (previous step)

# apebs0 = # wlar, abs(avols0, apebs0, vols, q), bflipset-cons(bflipset, wlar), ebm-cons(avols0), ubi-io-inv(apebs0), unique-sqns(apebs0), valid-ebatbl(apebs0, wlar, vols, vtblpnum), valid-eraseq(apebs0, q), valid-eraseq(wlar, q), valid-eraseq(q), valid-global-sqn(apebs0, vtblpnum0), valid-vtbl(apebs0, vols, wlar, vtblpnum), valid-wl(apebs0, wlar) ⊦ ∀ vols0, wlar0, q0, bflipset0, vtblpnum3, sqnum, vtblpnum4, vtblpnum5, err. ( err = ESUCCESS → # wlar = # wlar0 ∧ valid-global-sqn(apebs0, sqnum) ∧ valid-wl(apebs0, wlar0) ∧ valid-eraseq(q0) ∧ valid-eraseq(wlar0, q0) ∧ valid-eraseq(apebs0, q0) ∧ ¬ VTBL_VOLID ∈ vols0 ∧ bflipset-cons(bflipset0, wlar0) ∧ valid-ebatbl(apebs0, wlar0, vols0, vtblpnum3) ∧ valid-vtbl(apebs0, vols0, wlar0, vtblpnum3) ∧ vtblpnum4 = LEB_SIZE ∧ vtblpnum5 = EB_PAGE_SIZE) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → is-max(apebs0, vols0, wlar0, q0, bflipset0, vtblpnum3, sqnum) ∧ q0.lebrefs ⊆ q.lebrefs ∧ vols ⊆ vols0 ∧ vols0⌈vols, q⌉) → ( err = ESUCCESS → (∃ avols. avols0 ⊆ avols ∧ ebm-cons(avols) ∧ ⟨ebm_recover#(; avols; err0)⟩ (abs(avols, apebs0, vols0, q0) ∧ ESUCCESS = err0))) ∧ (err ≠ ESUCCESS → (∀ avols. ⟨ebm_recover#(; avols1; err0)⟩ (avols = avols1 ∧ err = err0))), VTBL_VOLID ∈ vols

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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