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Proof step 78 from proof recovery (previous step)

# wlar = # wlar0, # apebs0 = # wlar0, (vols0[v][m] = unmapped ⊃ (v × m ∈ q0 ⊃ unmapped;erased) ;mapped(apebs0[vols0[v][m].pnum].data, (avols0[v][m].mapped? ⊃ avols0[v][m].fill;apebs0[vols0[v][m].pnum].fill)) ) = mapped(buf, m0), m < # absf(v, avols0[v], apebs0, vols0[v], q0, # vols0[v]), m < # vols0[v], abs(avols0, apebs0, vols, q), bflipset-cons(bflipset0, wlar0), bflipset-cons(bflipset, wlar), ebm-cons(avols0), is-max(apebs0, vols0, wlar0, q0, bflipset0, vtblpnum3, sqnum), ubi-io-inv(apebs0), unique-sqns(apebs0), valid-ebatbl(apebs0, wlar0, vols0, vtblpnum3), valid-ebatbl(apebs0, wlar, vols, vtblpnum), valid-eraseq(apebs0, q0), valid-eraseq(wlar0, q0), valid-eraseq(q0), valid-eraseq(apebs0, q), valid-eraseq(wlar, q), valid-eraseq(q), valid-global-sqn(apebs0, sqnum), valid-global-sqn(apebs0, vtblpnum0), valid-vtbl(apebs0, vols0, wlar0, vtblpnum3), valid-vtbl(apebs0, vols, wlar, vtblpnum), valid-wl(apebs0, wlar0), valid-wl(apebs0, wlar), v ∈ vols0, vols ⊆ vols0, q0.lebrefs ⊆ q.lebrefs, vols0⌈vols, q⌉ ⊦ VTBL_VOLID ∈ vols, VTBL_VOLID ∈ vols0, # buf = LEB_SIZE ∧ m0 ≤ LEB_SIZE ∧ is-aligned(m0, EB_PAGE_SIZE) ∧ range=(buf, m0, emptyleb, 0, LEB_SIZE - m0)

Heuristic if-then-else split applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 3

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